EWT | Academic Question

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Question (11)
QN0026287
A sound wave with larger amplitude appears
  • (A) softer
  • (B) louder
  • (C) shriller
  • (D) slower

Correct Answer: B
Explanation:

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Question (12)
QN0026288
A sound wave with higher frequency appears
  • (A) louder
  • (B) softer
  • (C) shriller
  • (D) slower

Correct Answer: C
Explanation:

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Question (13)
QN0026289
If the frequency of a wave doubles, its time period becomes
  • (A) double
  • (B) half
  • (C) four times
  • (D) unchanged

Correct Answer: B
Explanation:

Frequency and time period are inversely proportional.

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Question (14)
QN0026290
The speed of sound is given by
  • (A) v=f/T
  • (B) v=λ/T
  • (C) v=fλ
  • (D) v=T/λ

Correct Answer: C
Explanation:

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Question (15)
QN0026291
A sound wave has wavelength 4 m and frequency 80 Hz. Speed is
  • (A) 160 m/s
  • (B) 240 m/s
  • (C) 320 m/s
  • (D) 640 m/s

Correct Answer: C
Explanation:

v = fλ = 80 × 4 = 320 m/s

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Question (16)
QN0026292
The bouncing back of sound after striking a surface is called
  • (A) absorption
  • (B) reflection
  • (C) refraction
  • (D) dispersion

Correct Answer: B
Explanation:

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Question (17)
QN0026293
Reflection of sound follows
  • (A) laws of reflection
  • (B) laws of gravitation
  • (C) Ohm’s law
  • (D) Newton’s law only

Correct Answer: A
Explanation:

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Question (18)
QN0026294
An echo is heard only if the reflected sound reaches the ear after at least
  • (A) 0.01 s
  • (B) 0.05 s
  • (C) 0.1 s
  • (D) 1 s

Correct Answer: C
Explanation:

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Question (19)
QN0026295
Minimum distance required to hear a distinct echo when speed of sound is 340 m/s is approximately
  • (A) 8.5 m
  • (B) 17 m
  • (C) 34 m
  • (D) 68 m

Correct Answer: B
Explanation:

Distance = vt/2 = 340 × 0.1 / 2 = 17 m

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Question (20)
QN0026296
A person hears an echo after 2 seconds. If speed of sound is 340 m/s, distance of reflector is
  • (A) 170 m
  • (B) 340 m
  • (C) 510 m
  • (D) 680 m

Correct Answer: B
Explanation:

Distance = vt/2 = 340 × 2 / 2 = 340 m

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