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Question (11)

QN0026217

A horizontal straight line on a position-time graph indicates:

(A) Uniform motion
(B) Accelerated motion
(C) Object at rest
(D) Circular motion

Correct Answer: C

Explanation:

A horizontal line indicates constant position, meaning the object is at rest.

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Question (12)

QN0026218

A straight line parallel to the time axis on a velocity-time graph indicates:

(A) Constant acceleration
(B) Constant velocity
(C) Increasing velocity
(D) Decreasing velocity

Correct Answer: B

Explanation:

A horizontal line on a velocity-time graph shows that velocity remains constant.

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Question (13)

QN0026219

The area under a velocity-time graph gives:

(A) Velocity
(B) Acceleration
(C) Displacement
(D) Speed

Correct Answer: C

Explanation:

Area under a velocity-time graph represents displacement.

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Question (14)

QN0026220

A vehicle starts from rest and accelerates at 2 m s⁻² for 8 s. Its final velocity is:

(A) 8 m s⁻¹
(B) 12 m s⁻¹
(C) 16 m s⁻¹
(D) 20 m s⁻¹

Correct Answer: C

Explanation:

Final velocity = u + at = 0 + (2 × 8) = 16 m s⁻¹.

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Question (15)

QN0026221

A stone dropped from rest acquires a velocity of 19.6 m s⁻¹ after 2 s. The acceleration due to gravity taken is:

(A) 4.9 m s⁻²
(B) 9.8 m s⁻²
(C) 19.6 m s⁻²
(D) 39.2 m s⁻²

Correct Answer: B

Explanation:

Acceleration = (19.6 – 0)/2 = 9.8 m s⁻².

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Question (16)

QN0026222

A car moving at 12 m s⁻¹ accelerates uniformly at 3 m s⁻² for 4 s. Distance travelled during this interval is:

(A) 48 m
(B) 72 m
(C) 96 m
(D) 120 m

Correct Answer: B

Explanation:

Distance = ut + ½at² = (12 × 4) + ½ × 3 × 16 = 48 + 24 = 72 m.

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Question (17)

QN0026223

A vehicle moving at 20 m s⁻¹ is brought to rest with uniform acceleration of –4 m s⁻². The stopping distance is:

(A) 25 m
(B) 50 m
(C) 75 m
(D) 100 m

Correct Answer: B

Explanation:

Using v² = u² + 2as, 0 = 400 – 8s, so s = 50 m.

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Question (18)

QN0026224

In uniform circular motion, which quantity continuously changes?

(A) Speed only
(B) Distance only
(C) Direction of velocity only
(D) Radius only

Correct Answer: C

Explanation:

In uniform circular motion, speed remains constant but the direction of velocity changes continuously.

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Question (19)

QN0026225

A runner completes half a round on a circular track of radius 14 m. The magnitude of displacement is:

(A) 14 m
(B) 28 m
(C) 44 m
(D) 88 m

Correct Answer: B

Explanation:

After half a revolution, displacement equals the diameter = 2 × 14 = 28 m.

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Question (20)

QN0026226

A car takes 5 s to increase its speed from 10 m s⁻¹ to 20 m s⁻¹. During this interval, the average velocity is:

(A) 10 m s⁻¹
(B) 15 m s⁻¹
(C) 20 m s⁻¹
(D) 25 m s⁻¹

Correct Answer: B

Explanation:

For constant acceleration, average velocity = (u + v)/2 = (10 + 20)/2 = 15 m s⁻¹.

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Question (11)

A horizontal straight line on a position-time graph indicates:

Explanation:

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Question (12)

A straight line parallel to the time axis on a velocity-time graph indicates:

Explanation:

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Question (13)

The area under a velocity-time graph gives:

Explanation:

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Question (14)

A vehicle starts from rest and accelerates at 2 m s⁻² for 8 s. Its final velocity is:

Explanation:

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Question (15)

A stone dropped from rest acquires a velocity of 19.6 m s⁻¹ after 2 s. The acceleration due to gravity taken is:

Explanation:

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Question (16)

A car moving at 12 m s⁻¹ accelerates uniformly at 3 m s⁻² for 4 s. Distance travelled during this interval is:

Explanation:

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Question (17)

A vehicle moving at 20 m s⁻¹ is brought to rest with uniform acceleration of –4 m s⁻². The stopping distance is:

Explanation:

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Question (18)

In uniform circular motion, which quantity continuously changes?

Explanation:

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Question (19)

A runner completes half a round on a circular track of radius 14 m. The magnitude of displacement is:

Explanation:

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Question (20)

A car takes 5 s to increase its speed from 10 m s⁻¹ to 20 m s⁻¹. During this interval, the average velocity is:

Explanation:

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