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Net displacement = 120 + 80 – 50 = 150 m east.
After one complete revolution, the cyclist returns to the starting point, so displacement is zero.
Displacement is a vector quantity and requires both magnitude and direction.
Average speed = Total distance/Total time = (180 + 120)/(3 + 2) = 300/5 = 60 km h⁻¹.
Net displacement is zero, so average velocity is zero.
Unequal distances covered in equal intervals indicate non-uniform motion.
54 km h⁻¹ = 15 m s⁻¹ and 72 km h⁻¹ = 20 m s⁻¹. Acceleration = (20 – 15)/10 = 0.5 m s⁻².
Acceleration = (10 – 25)/5 = –3 m s⁻².
Displacement = velocity × time = 20 × 15 = 300 m.
The slope of a position-time graph gives the velocity of the object.
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