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√2 is irrational and cannot be expressed as a fraction of two counting numbers.
Multiplying all sides of a Baudhāyana triple by the same positive integer gives another Baudhāyana triple.
The nth odd number is 2n – 1. Therefore, the 25th odd number is 49.
Side = √32 = 4√2. Diagonal = 4√2 × √2 = 8 cm.
Diagonal = √(9² + 12²) = √225 = 15 cm.
Half diagonals are 8 cm and 15 cm. Side = √(8² + 15²) = 17 cm.
Using Pythagoras theorem: 6² + x² = (x + 2)². Solving gives x = 8 units.
Fermat's Last Theorem states that xⁿ + yⁿ = zⁿ has no positive integer solutions for n > 2.
Since 11² + 60² = 61², the numbers form a Baudhāyana triple.
Original area = 16 cm². After first doubling = 32 cm². After second doubling = 64 cm².
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