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Area of original square = 7² = 49 cm². The square on the diagonal has double the area, i.e., 98 cm².
The required square has half the area of the original square. Half of 72 cm² = 36 cm².
Area of a square in terms of diagonal d is d²/2. Thus, area = 10²/2 = 50 cm².
Hypotenuse = √(2 × 5²) = √50. Since 7² < 50 < 8², the hypotenuse lies between 7 and 8.
For an isosceles right triangle, c² = 2a². So, 98 = 2a² ⇒ a² = 49 ⇒ a = 7 units.
Required side = √(6² + 8²) = √100 = 10 cm.
(9,12,15) = 3 × (3,4,5), so it is a scaled version of the primitive triple (3,4,5).
The numbers 8, 15 and 17 have no common factor greater than 1, so the triple is primitive.
Other side² = 29² – 20² = 841 – 400 = 441. Hence, the side is 21 cm.
Diagonal = side × √2. Therefore, side = 6√2/√2 = 6 cm.
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