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If the number is ab, then the difference is (10a + b) – (10b + a) = 9(a – b), which is always divisible by 9.
83 – 38 = 45 and 45 ÷ 9 = 5.
For number ab, (10a + b) + (10b + a) = 11(a + b), which is always divisible by 11.
abc + bca + cab = 111(a + b + c) = 3 × 37 × (a + b + c). Hence, it is divisible by both 3 and 37.
428428 = 428 × 1001 and 1001 = 7 × 11 × 13. Therefore, the final quotient is 428.
If all 40 animals were hens, there would be 80 legs. The extra 32 legs come from horses. Since each horse contributes 2 extra legs, there are 16 horses.
Let the son's age be x years. Then, 4x + 10 = 2(x + 10). Solving gives x = 10 years.
Let the poorer friend have x cows. Then the richer friend has 3x cows. After transfer, x + 6 = 3x – 6, giving x = 6.
Revenue = 200 × 50 = ₹10000. Total cost = ₹5000 + 200 × ₹15 = ₹8000. Profit = ₹2000.
The numerator is 1 + 3 + 5 + 7 = 16 and the denominator is 9 + 11 + 13 + 15 + 17 = 65. Hence, the fraction equals 16/65.
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