EWT | Academic Question

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Question (11)
QN0029523
Choose the correct statement for any two-digit number with distinct digits.
  • (A) The difference of the number and its reverse is always divisible by 7.
  • (B) The difference is always divisible by 9.
  • (C) The sum is always divisible by 9.
  • (D) The product is always divisible by 11.

Correct Answer: B
Explanation:

If the number is ab, then the difference is (10a + b) – (10b + a) = 9(a – b), which is always divisible by 9.

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Question (12)
QN0029524
If the number 83 is reversed and subtracted, the quotient obtained after dividing the difference by 9 is
  • (A) 3
  • (B) 5
  • (C) 6
  • (D) 7

Correct Answer: B
Explanation:

83 – 38 = 45 and 45 ÷ 9 = 5.

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Question (13)
QN0029525
The sum of a two-digit number and its reverse is always divisible by
  • (A) 5
  • (B) 7
  • (C) 9
  • (D) 11

Correct Answer: D
Explanation:

For number ab, (10a + b) + (10b + a) = 11(a + b), which is always divisible by 11.

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Question (14)
QN0029526
For any three-digit number abc, the sum abc + bca + cab is always divisible by
  • (A) 27 only
  • (B) 37 only
  • (C) 37 and 3
  • (D) 11 only

Correct Answer: C
Explanation:

abc + bca + cab = 111(a + b + c) = 3 × 37 × (a + b + c). Hence, it is divisible by both 3 and 37.

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Question (15)
QN0029527
A six-digit number is formed as 428428. After dividing successively by 7, 11 and 13, the final quotient is
  • (A) 42
  • (B) 428
  • (C) 84
  • (D) 4284

Correct Answer: B
Explanation:

428428 = 428 × 1001 and 1001 = 7 × 11 × 13. Therefore, the final quotient is 428.

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Question (16)
QN0029528
A farm has 40 animals consisting of horses and hens. If there are 112 legs altogether, the number of horses is
  • (A) 12
  • (B) 16
  • (C) 20
  • (D) 24

Correct Answer: B
Explanation:

If all 40 animals were hens, there would be 80 legs. The extra 32 legs come from horses. Since each horse contributes 2 extra legs, there are 16 horses.

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Question (17)
QN0029529
A mother is four times as old as her son. After 10 years, she will be twice his age. The son's present age is
  • (A) 8 years
  • (B) 10 years
  • (C) 12 years
  • (D) 14 years

Correct Answer: B
Explanation:

Let the son's age be x years. Then, 4x + 10 = 2(x + 10). Solving gives x = 10 years.

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Question (18)
QN0029530
Two friends have cows. One says, “You have three times as many cows as I do.” If 6 cows are transferred from the richer friend to the poorer friend, both have equal cows. The poorer friend originally had
  • (A) 6
  • (B) 8
  • (C) 12
  • (D) 18

Correct Answer: A
Explanation:

Let the poorer friend have x cows. Then the richer friend has 3x cows. After transfer, x + 6 = 3x – 6, giving x = 6.

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Question (19)
QN0029531
A dosa seller spends ₹5000 as fixed cost per day and ₹15 per dosa. If 200 dosas are sold at ₹50 each, the profit is
  • (A) ₹1000
  • (B) ₹1500
  • (C) ₹2000
  • (D) ₹2500

Correct Answer: C
Explanation:

Revenue = 200 × 50 = ₹10000. Total cost = ₹5000 + 200 × ₹15 = ₹8000. Profit = ₹2000.

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Question (20)
QN0029532
The fraction (1 + 3 + 5 + 7)/(9 + 11 + 13 + 15 + 17) is equal to
  • (A) 4/9
  • (B) 8/13
  • (C) 16/65
  • (D) 1/2

Correct Answer: C
Explanation:

The numerator is 1 + 3 + 5 + 7 = 16 and the denominator is 9 + 11 + 13 + 15 + 17 = 65. Hence, the fraction equals 16/65.

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