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Let each base angle be x°. Then vertex angle = 4x°. So, x + x + 4x = 180°. Hence x = 30° and the vertex angle = 120°.
Three equal corresponding sides satisfy the SSS congruence criterion.
In an equilateral triangle, every median is also an altitude, angle bisector and perpendicular bisector.
Let the vertex angle be x°. Then each base angle = (x − 15)°. So, x + (x − 15) + (x − 15) = 180°. Hence x = 70°.
ASA requires two equal angles and the included side.
Let each base angle be x°. Then vertex angle = 2x°. So, x + x + 2x = 180°. Hence x = 45° and the vertex angle = 90°.
Two sides are equal, so the triangle is isosceles.
RHS applies only to right-angled triangles.
This is the SAS congruence criterion.
All equilateral triangles are similar, but they are congruent only if their corresponding side lengths are equal.
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