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Total of 9 observations = 18 × 9 = 162. Total of remaining 8 = 17 × 8 = 136. Removed observation = 162 − 136 = 26.
Original median = 14. Adding 5 to every value increases the median by 5. New median = 19.
A missing value is different from a score of zero. The average should be calculated using only the tests actually attended.
Total = 18 × 5 = 90. Sum of known numbers = 66. Therefore, x = 90 − 66 = 24.
The arithmetic mean always lies between the smallest and largest values of a data set.
Mean = (6 + 8 + 10 + 12 + 14 + 16) ÷ 6 = 11. Median = (10 + 12) ÷ 2 = 11. Difference = 0.
A double-bar graph uses the same scale and places bars side by side for easy comparison.
Multiplying every observation by 2 also doubles the mean. Hence, the new mean = 30.
A dot plot displays each data value, making it easy to observe variability, clustering and repeated values.
The value 39 is an outlier. The median (6) is less affected by the outlier and better represents the centre of the data.
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