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Each remaining square produces 8 new squares. Therefore, (R_4 = 8^4 = 4096).
The number of remaining triangles follows the pattern (3^n). Hence, at Step 4, the number is (3^4 = 81).
Each step retains (8/9) of the previous area. Thus, area after Step 2 is ((8/9)^2 = 64/81) sq. unit.
The number of sides becomes four times at each step. Hence, number of sides at Step 3 is (3 \times 4^3 = 192).
When viewed from the top, a cube shows one of its square faces.
A cylinder gives a circular top view and a rectangular side view.
An (n)-sided prism has (2n) vertices. For an octagonal prism, vertices (= 2 \times 8 = 16).
Since a prism has (2n) vertices, (2n = 24). Therefore, (n = 12).
A pyramid with an (n)-sided base has (n+1) faces. Thus, faces (= 6+1 = 7).
If total faces are 9, then (n+1 = 9). Hence, (n = 8), so the base is an octagon.
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